Find the number of CORRECT order against ment | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $(i)$ $D_2O$ ($2 	imes 1 + 8 = 10$ electrons) and $H_2O$ ($2 	imes 1 + 8 = 10$ electrons). So,$D_2O = H_2O$ is $CORRECT$.$(ii)$ The enthalpy of

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) $(i)$ $D_2O$ ($2 	imes 1 + 8 = 10$ electrons) and $H_2O$ ($2 	imes 1 + 8 = 10$ electrons). So,$D_2O = H_2O$ is $CORRECT$.$(ii)$ The enthalpy of formation $|\Delta H_f|$ for $D_2O$ is higher than $H_2O$ due to stronger $O-D$ bonds compared to $O-H$ bonds. So,$D_2O > H_2O$ is $CORRECT$.$(iii)$ The enthalpy of vaporization $|\Delta H_{vaporization}|$ for $D_2O$ is higher than $H_2O$ due to stronger intermolecular hydrogen bonding in $D_2O$. So,$D_2O > H_2O$ is $CORRECT$.$(iv)$ The density of $D_2O$ $(1.107 \ g/mL)$ is higher than $H_2O$ $(1.000 \ g/mL)$. So,$D_2O > H_2O$ is $CORRECT$.$(v)$ Molecular mass of $D_2O$ $(20 \ u)$ is higher than $H_2O$ $(18 \ u)$. So,$D_2O > H_2O$ is $CORRECT$.All $5$ statements are $CORRECT$.

Find the number of $CORRECT$ order against mentioned property :-
$(i)$ $D_2O = H_2O$ (number of electrons)
$(ii)$ $D_2O > H_2O$ $(|\Delta H_f|)$
$(iii)$ $D_2O > H_2O$ $(|\Delta H_{vaporization}|)$
$(iv)$ $D_2O > H_2O$ (density)
$(v)$ $D_2O > H_2O$ (Molecular mass)

Similar Questions

In comparison to the zeolite process for the removal of permanent hardness,the synthetic resins method is

Which salt does not cause hardness in water?

In the removal of temporary hardness of a sample containing $Ca^{2+}$,what is the number of moles of $Ca(OH)_2$ used per mole of $Ca(HCO_3)_2$ removed?

The solubility of an ionic compound is compared in heavy water $(D_2O)$ and simple water $(H_2O)$. It is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the number of $CORRECT$ order against mentioned property :-$(i)$ $D_2O = H_2O$ (number of electrons)$(ii)$ $D_2O > H_2O$ $(|\Delta H_f|)$$(iii)$ $D_2O > H_2O$ $(|\Delta H_{vaporization}|)$$(iv)$ $D_2O > H_2O$ (density)$(v)$ $D_2O > H_2O$ (Molecular mass)